The reaction `A(g) + 2B(g) rarr C(g) + D(g)` is an elementary process. In an experiment involvig this reaction, the initial partial pressure of `A` and `B` are `p_(A) = 0.60 atm` and `p_(B) = 0.80 atm`, respectively. When `p_(C ) = 0.20 atm`, the rate of reaction relative to the initial rate is

Options

A. `(1)/(6)`
B. `(1)/(48)`
C. `(1)/(4)`
D. `(1)/(24)`

Answer

1

Explanation

Initial Rate`=k[A][B]^(2)`
Rate `1=k[0.60][0.80]^(2)" " ….(i)`
Rate `2=k[0.60][0.80]^(2)" "….(ii)`
Given `Rxxn`
`{:(A(g),+,2B(g),rarr,C(g),+,D(g),),(0.60atm,,0.80atm,,0,,0,t=0),((0.60-0.2),,(0.80-0.40),,0.20,,0.20atm,),(0.40atm,,0.40atm,,0.20atm,,0.20atm,t=1):}` ltBRgt Put value of pressure of `t=t` in rate equation `(II)`
Rate `2=k(40][40]^(2)`
`("Rate2")/("Rate 1")=(k[40][40]^(2))/(k[60][80]^(2))`
`(Rate2)/(Rate1)=(2)/(3)xx(1)/(4)=(1)/(6)`