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A subtance undergoes first order decompo...

A subtance undergoes first order decomposition involving two parallel first order reaction as `:`

The mole percent of B in the products is `:`

A

23.17

B

76.68

C

30.16

D

69.84

Text Solution

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The correct Answer is:
2
`(k_(1)xx100)/(k_(1)+k_(2))=(1.28xx10^(-4))/(1.25xx10^(-4)+3.80xx10^(-5))=76.83`
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