A catalyst lowers the enrgy of activation by `25%`, temperature at which rate of uncatalysed reaction will be equal to that of the catalyst one at `27^(@)C` is `:`

Options

A. `400 ^(@)C`
B. `127^(@)C`
C. `300^(@)C`
D. `227^(@)C`

Answer

2

Explanation

`(E_(a))/(T_(1))=(E_(a)^(@))/(T_(2))`
`rArr" "(T_(2))/(T_(1))=(E_(a)^(@))/(E_(a))=(75)/(100)=0.75," "(300)/(T_(1))=0.75`
`rArr" "T_(1)=(300)/(0.75)=400K=127^(@)C`