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For the reaction 2NO(2)+F(2)rarr 2NO(2)F...

For the reaction `2NO_(2)+F_(2)rarr 2NO_(2)F`, following mechanism has been provided:
`NO_(2)+F_(2) overset("slow")(rarr) NO_(2)F+F`
`NO_(2)+Foverset("fast")(rarr) NO_(2)F`
Thus rate expression of the above reaction can be writtens as:

A

`r=k[NO_(2)]^(2)[F_(2)]`

B

`r=k[NO_(2)]`

C

`r=k[[NO_(2)][F_(2)]`

D

`r=k[F_(2)]`

Text Solution

Verified by Experts

The correct Answer is:
3

Rate is given by the slowest step of the reaction so rate is `r=k[NO_(2)][F_(3)]`.
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