For the reaction,
`2NO(g) + 2H_(2)(g) rarr N_(2)(g) + 2H_(2)O(g)`
The rate expression can be written in the following ways:
`(d[N_(2)])/(d t) = k_(1)[NO][H_(2)], (d[H_(2)O])/(d t) = k_(2)[NO][H_(2)]`
`- (d[NO])/(d t) = k_(3)[NO][H_(2)], -(d[H_(2)])/(d t) = k_(4)[NO] [H_(2)]`
The relationship between `k_(1), k_(2), k_(3), k_(4)` is

Options

A. `k=k_(1)=k'_(1)=k''_(1)`
B. `k=2k_(1)=k'_(1)=k''_(1)`
C. `k=2k'_(1)=k_(1)=k''_(1)`
D. `k=k_(1)=k_(1)=2k''_(1)`

Answer

2

Explanation

`-(1)/(2)(d[NO])/(dt)=-(1)/(2)(d[H_(2)])/(dt)=(d[N_(2)])/(dt)=(1)/(2)(d[H_(2)O])/(dt)`
`(1)/(2)k_(1)^(-1)[NO][H_(2)]=(1)/(2)k_(1)^(11)[NO][H_(2)]=k_(1)[NO][H_(2)]=(1)/(2)k[NO][H_(2)]" ":.k_(1)^(1)=k_(1)^(11)=2k_(1)k`