Milk turns sour at `40^(@)C` three times as faster as `0^(@)C`. Hence `E_(a)` in cal of process of turning of milk sour is `:`

Options

A. `(2.303xx2xx313xx273)/(40)log3`
B. `(2.303xx2xx313xx273)/(40)log.(1)/(3)`
C. `(2.303xx2xx40)/(273xx313)log3`
D. None of the above

Answer

1

Explanation

Milk tum sour at `40^(@)C` three times faster as `0^(@)C`
Then `("rate at "40^(@)C)/("rate at "0^(@)C)=(k_(40^(@)C))/(k_(0^(@)C))`
`E_(a)=(2.303RT_(1)T_(2))/((T_(2)-T_(1)))log((k_(40^(@)C))/(k_(0^(@)C)))`
`=E_(a)=(2.303xx2xx313xx273log(3))/(40)`