Evaluate each of the following integral: `int_0^(pi//2)sin^2x\ dx`

Explanation

`\int_{0}^{\frac{\pi}{2}} \sin ^{2} x d x `


`=\frac{1}{2} \int_{0}^{\frac{\pi}{2}} 2 \sin ^{2} x d x`



We know that `\cos 2 x=1-2 \sin ^{2} x \Rightarrow 2 \sin ^{2} x=1-\cos 2 x`



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