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Mixture of volatile components A and B h...

Mixture of volatile components A and B has total pressure ( in Torr ) `p=265-130x_(A),` where `X_(A)` is mole fraction of `A` in mixture . Hence `P_(A)^(@)+P_(B)^(@)=` ( in T o r r).

A

265

B

135

C

400

D

150

Text Solution

Verified by Experts

The correct Answer is:
C
`P=X_(A)P_(A)^(@)+X_(B)P_(B)^(@)=(P_(A)^(@)-P_(B)^(@))X_(A)+P_(B)^(@)`
So`" "P_(B)^(@)=265`
`P_(A)^(@)-P_(B)^(@)=-130" "P_(A)^(@)=135`
`P_(A)^(@)+P_(B)^(@)=400`
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