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If the freezing point of 0.1 M HA(aq) so...

If the freezing point of `0.1 M HA(aq)` solution is `-0.2046^(@)C` then `pH` of solution is
`(` If `K_(f)` water `=1.86mol^(-1)kg^(-1))`

A

1

B

1.3

C

1.7

D

2

Text Solution

Verified by Experts

The correct Answer is:
4
`DeltaT_(f)=` molality `xxK_(f)xxi`
`i=1+(n-1)alpha`
`alpha=0.1" "[H^(+)]=Calpha`

`" "[H^(+)]=0.1xx0.1=10^(-2)`
`pH=-log[H^(+)]`
`pH=2`
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