At STP the volume of nitrogen gas required to cover a sample of silica gas, assuming larngmulr monolayer adsorption is found to be `1.30 gcm^(-2) g^(-1)` of the gel. The area occupied by a nitrogen molecule is `0.16nm^(2)`. What is the surface area per gram of silica gel ?
A
`5.568m^(2)g^(-1)`
B
`3.48m^(2)g^(-1)`
C
`1.6m^(2)g^(-1)`
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
1
No. of molecule per gm of `N_(2)` in monolayer `=(6xx10^(23))/(22400)xx1.30=3.48xx10^(19)` area of a molecule `=1.6xx10^(19)m^(2)` `:." "` Area covered by molecule per gram`=3.48xx10^(19)xx1.6xx10^(-19)=5.568m^(2)` `:. " "`Surface are `=5.568m^(2)g^(-1)`
At 1 atm and 273 K the volume of nitrogen gas required to cover a sample of silica gel, assuming Langmuir monolayer adsorption , is found to be 1.30 cm^(3)g^(-1) of the gel. The area occupoied by a nitrogen molecule os 0.16nm^(2) . Find out the no. of surface sites occupied per molecule of H_(2) .
1.30 cm^(3) of N_(2) gas at STP is adsorbed per gram of silica gel. The area occupied by nitrogen molecule is 0.16 nm^(2) . What is the surface area per gram of silica gel ? (N_(A)=6.023xx10^(23))
The volume of nitrogen gas Vm (at STP) reqired to cover a sample of silica gel with a monomolecular layer is 129cm^(3)g^(-1) of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies 16.23xx10^(-20)m^(2) .
The volume of nitrogen gas Um (measured at STP) required to cover a sample of silica get with a mono-molecular layer is 129 cm^(3) g^(-1) of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies 16.2 xx 10^(-20) m^(2).
