`3.6` gram of oxygen is adsorbed in `1.2g` of metal powder. What volume of oxygen adsorbed per gram of the adsorbent at `STP` ?
A
`0.19Lg^(-1)`
B
`1 Lg^(-1)`
C
`2.1Lg^(-1)`
D
none of these
Text Solution
Verified by Experts
The correct Answer is:
3
Mass of `O_(2)` per gram of adsorbent `=(3.6)/(1.2)=3` No. of moles of `O_(2)` per gram of adsorbent `=(3)/(32)` Volume of `O_(2)` per gram of adsorbent `=(3)/(32)xx(0.082.273)/(1)=2.10`
3.6 gram of oxygen of adsorbed on 1.2 g of metal powder. What volume of oxygen adsorbed per gram of the adsorbent at 1 atm and 273 K ?
3.12 g of oxygen is adsorbed on 1.2 g of platinum metal. The volume of oxygen adsorbed per gram of the adsorbent at 1 atm and 300 K is L is _____________. [R = 0.0821 L atm K^(-1) "mol"^(-1) ]
3.12g of oxygen is adsorbed on 1.2g Pt. What volume of oxygen per gram of adsorbent is adsorbed at 1atm, 300k?
A sample of 16 g charcoal was brought into contact with CH_(4) gas contained in a vessel of 1 litre at 27^(@) C . The presses of gas was found to fall from 760 to 608 torr. The density of chacoal sample is 1.6 g//m^(3) . What is the volume of the CH_(4) gas adsorbed per gram of the adsorbent at 608 torr and 27^(@)C ?
Three grams of oxygen are adsorbed on 1.2 g of charcoal powder at 300K and 0.7 atm.Express the mass,number of moles and volume of oxygen at 300K, 0.7 atm and at STP adsorbed per gram of the adsrbent.
The adsorption isotherm for a gas is given by the relation x=ap//(1+bp) where x is mole of gas adsorbed per gram of the adsorbent, p is the pressure of the gas, and a and b are constants. Then x
How many grams of oxygen will be formed by the action of 12g of sodium peroxide on water? Calculate also the volume of the gas at NTP.
