The pressure of the gas was found to decrease from 720 to `480 m`. When `5g` of sample of activated charcoal was kept in a flask of one litre capacity maintained at `27^(@)C` . If the density of charcoal at `1.25 gm//mL`. The volume of gas adsorbed per `gm` of charcoal at `480 mm` of `Hg` is
A
`80.03 mL`
B
`32.20 mL`
C
`100.08mL`
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
3
`V_(2)=(P_(1)V_(1))/(P_(2))=(720xx1000)/(480)=1500ml` Volume of gas in the flask `=1000-` volume of charcoal `1000-(5)/(1.25)=996ml` Total volume of gas adsorbe by charcoal `=1500-996=504ml` Volume of gas adsorbe by per gram of charcoal `=(504)/(5)=100.08ml` `V_(2)=(P_(1)V_(1))/(P_(2))=(720xx1000)/(480)=1500ml`
The pressure of the gas was found to decrease from 720 to 480 mm. When 5g of sample of activated charcoal was kept in a flask of one litre capacity maintained at 27^(@)C . If the density of charcoal is 1.25 gm//mL . The volume of gas adsorbed per gm of charcoal at 480 mm of Hg is :
A sample of 16 g charcoal was brought into contact with CH_(4) gas contained in a vessel of 1 litre at 27^(@) C . The presses of gas was found to fall from 760 to 608 torr. The density of chacoal sample is 1.6 g//m^(3) . What is the volume of the CH_(4) gas adsorbed per gram of the adsorbent at 608 torr and 27^(@)C ?
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In an Adsorption experiment a graph between log x//m versus log P was found to be linear with a slope of 45^(@) the intercept of the log x//m was found to be 0.3010 . Calculate the amount of gas adsorbed per gm of charcoal under a pressure of 0.6 bar.
Two moles of an idea gas is initially in state A having pressure 1.01xx10^(5)N//m^(2) and temperature 3O0k keeping pressure constant the gas is taken to state B temperature at B is 500K the gas is then taken to state C in such a way that its temperature increases and volume decreases also from B To c the magnitude of (dT)/(dV) increases the volume of gas at C is equal to volume of gas at A now the gas is taken to initial state A keeping volume constant A total of 1200 J of heat is with drawn from the sample in the cyclic process the T-V graph for the cyclic process and work done in path B to C are respectively (take R=8.3J//k//mol)
