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The freezing point of 0.08 molal aq NaHS...

The freezing point of 0.08 molal aq `NaHSO_(4)` solution is `-0.372`. Calculate `alpha` (degree of dessociation) of `HSO_(4)^(-)` given `alpha` (degree of dissociation) of `NaHSO_(4)` is `100%` & `K_(f)` for `H_(2)O=1.86` `(K)/(m)`. Give answer after multiplying by 10.

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