Home
Class 12
CHEMISTRY
henry's law constant for CO(2) in water ...

henry's law constant for `CO_(2)` in water is `2.5xx10^(8)` Pa at `298K` calcualte mmole of `CO_(2)` dissolbed in 144 g water at 2.5 atm pressure at 298K. [take 1 atm `=10^(6)(N)/(m^(2))` or Pa]

Text Solution

Verified by Experts

The correct Answer is:
8
Promotional Banner

Similar Questions

Explore conceptually related problems

Henry's law constant for CO_(2) in water is 2.5xx10^(8)Pa at 298K . Calculate mmole of CO_(2) dissolved in 14g water at 2.5atm pressure at 298K . [Take 1atm=10^(5)N//m^(2) or Pa ]

Henry's law constant for CO_(2) in water is 1.67xx10^(8) Pa at 298 K . Calculate the quantity of CO_(2) in 500mL of soda water when packed under 2.5atm CO_(2) pressure at 298 K .

Henry's law constant for CO_(2) in water is 1.6times10^(8)Pa at 298K . The quantity of CO_(2) in 500g of soda water when packed under 3.2 bar pressure at 298K is

Henry's law constant of CO_2 in water at 298K is 5/3K bar. IF pressure of CO_2 is 0.01 bar, find its mole fraction.

The Henry's law constant for the solubility of N_(2) gas i water at 298K is 1xx10^(5) atm. The mole fraction of N_(2) air is 0.8 . The number of mole of N_(2) of dissolved in 10 mole of water at 298K and 5 atm. are x xx10^(4) . Find the value of x .

Henry 's law constant for the solubility of N_(2) gas in water at 298 K is 1.0 xx 10^(5) atm . The mole fraction of N_(2) in air is 0.6 . The number of moles of N_(2) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is a. 3.0 xx 10^(-4) b. 4.0 xx 10^(-5) c. 5.0 xx 10^(-4) d. 6.0 xx 10^(-6)