`int_(-1)^1|1-x|dx` is equal to `-2` b. `2` c. `0` d. `4`

Explanation

To solve the integral \( \int_{-1}^{1} |1 - x| \, dx \), we will follow these steps:

### Step 1: Analyze the absolute value function
The expression inside the absolute value is \( 1 - x \). We need to determine where this expression is positive or negative within the limits of integration \([-1, 1]\).

- \( 1 - x \) is positive when \( x < 1 \).
- \( 1 - x \) is zero when \( x = 1 \).
- \( 1 - x \) is negative when \( x > 1 \).
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