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if f(x)={{:(2+x,xge0),(2-x,xlt0):} then ...

if `f(x)={{:(2+x,xge0),(2-x,xlt0):}` then `lim_(x to 0) f(f(x))` is equal to

A

0

B

4

C

2

D

does not exist

Text Solution

Verified by Experts

The correct Answer is:
B
Let `phi(x)=f(f(x))`
`thereforephi(0^(+))=underset(xto0^(+))limf(f(x))=f(f(0^(+)))=f^(2^(+))=4`
`phi(0^(-))=underset(xto0)limf(f(x))=f(f(0^(-)))=f(2^(-))=4`
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