Evaluate the following integral: `int_0^1(1-x)/(1+x)dx`

Explanation

To evaluate the integral \( I = \int_0^1 \frac{1-x}{1+x} \, dx \), we can use the property of definite integrals that states:

\[ \int_0^a f(x) \, dx = \int_0^a f(a-x) \, dx \]

### Step 1: Apply the property of integrals

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