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CrO3 dissolves in aqueous NaOH to give...

`CrO_3` dissolves in aqueous NaOH to give

A

`Cr_(2)O_(7)^(2-)`

B

`CrO_(4)^(2-)`

C

`Cr(OH)_(3)^(2-)`

D

`Cr(OH)_(2)`

Text Solution

Verified by Experts

The correct Answer is:
2
`NaOH+CrO_(3)rarrNa_(2)CrO_(4)+H_(2)O`
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Cr)_(3) dissolved in aqueous NaOH to give:

Compound (A) C_(7)H_(8)O is insoluble in aqueous NaHCO_(3) and dissolves in aqueous NaOH and gives a characteristic colour with neutral FeCl_(3) . When treated with Br_(2) (A) forms compound (B) C_(7)H_(5)O Br_(3) . The structure of compound (B) would be :

Compound (A) C_(7)H_(8)O is insoluble in aqueous NaHCO_(3) and dissolves in aqueous NaOH and gives a characteristic colour with neutral FeCl_(3) . When treated with Br_(2) (A) forms compound (B) C_(7)H_(5)O Br_(3) . The most probable structure of compound A is :

Compound (A) C_(7)H_(8)O is insoluble in aqueous NaHCO_(3) and dissolves in aqueous NaOH and gives a characteristic colour with neutral FeCl_(3) . When treated with Br_(2) (A) forms compound (B) C_(7)H_(5)O Br_(3) . What could be the structure of compound (A) if neither dissolves in aq. NaHCO_(3) nor gives a characteristic colour with FeCl_(3) ?

Which element of the carbon family does not dissolve in aqueous NaOH to evolve hydrogen gas?

RESONANCE-D & F BLOCK ELEMENTS-INORGANIC CHEMISTRY(d & f- Block Elments)
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  2. In which of the following reaction "Philosopher's wool" is formed

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  5. The formula of azurite is :

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  6. Oxide of metal cation which is not amphoteric ?

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  7. The ratio of mass of a diamagnetic substance in a magnetic field to it...

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  8. CrO(4)^(2-) (yellow) changes to Cr(2)O(7)^(2-)(orange ) in pH=y . Henc...

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  9. An excess of Na(2)S(2)OO(3) react with aqueous CuSO(4) to give

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  11. Potassium manganate (K2MnO4) is formed when

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  12. Uub is the symbol for the element with atomic number-

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  13. Which of the following species has O-O bond?

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  16. Both [Ni(CO)4] and [Ni (CN)4]^(2-) are diamagnetic The hybridisation...

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  19. Match List I with List II and select the correct answer using the code...

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