Evaluate the following integral: `int_0^1|sin2pix|dx`

Explanation

Given:`int_0^1|sin2pix|dx`

`I=int_0^1|sin2pix|dx`

As we know that

`int_0^(2a)f(x)dx=2int_0^a f(x)dx` when `f(2a-x)=f(x)`

So, `f(1-x)=|sin(2pi-2pix)|`

`implies |-sin2pix|=|sin2pix|/(f(x))`

`I=2int_0^(1/2)|sin2pix|dx`

`I=2int_0^(1/2) sin2pix dx`

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