`[Cr(H_2 O)_6]Cl_3` (at no. of Cr = 24) has a magnetic moment of `3.83 B.M`. The correct distribution of `3d` electrons the chromium of the complex.

Options

A. `3d_(xy)^(1),3d_(yz)^(1),3d_(x x)^(1)`
B. `3d_(xy)^(1),3d_(yx)^(1),3d_(z^(2))^(1)`
C. `3d_((x^(2)-y^(2)))^(1),3d_(z^(2))^(1),3d_(zx)^(1)`
D. `3d_(xy)^(1),3d_((x^(2)-y^(2)))^(1),3d_(yz)^(1)`

Answer

1

Explanation

`[Cr(H_(2)O)_(6)]Cl_(3)` have `Cr^(3+)` having`d^(3)` configuration since it is octahedral complex . Thus electrons are filled in `t_(2g)` orbitals `(d_(xy)^(1),d_(yz)^(1),d_(zx)^(1))` . Thus it have configuration as `t_(2g)^(3)eg^(@)`