Match the List -I (containing anions ) with List -II (containing reagent used in testing ) using the codes as given below in the column.
`{:("List"-I,,"List"-II),(("anions"),,("reagents")),((a)S^(2-),,(p)"Barium chloride solution in presence of HCl"),((b)NO_(3)^(-),,(q)"Sodium nitroprusside"),((c)I^(-),,(r)"chlorine water and chloroform"),((d)SO_(4)^(2-),,(s)"iron"(II)"sulphate solution and conc."H_(2)SOS_(4)):}`
Code `:`

Options

A. `{:(,"(a)","(b)","(c)","(d)"),(,"(q)","(s)","(r)","(p)"):}`
B. `{:(,"(a)","(b)","(c)","(d)"),(,"(p)","(s)","(r)","(q)"):}`
C. `{:(,"(a)","(b)","(c)","(d)"),(,"(q)","(p)","(r)","(s)"):}`
D. `{:(,"(a)","(b)","(c)","(d)"),(,"(p)","(q)","(r)","(s)"):}`

Answer

1

Explanation

`(a)" "[Fe(CN)_(5)NO]^(2-)+S^(2-)rarr[Fe(CN)_(5)NO]^(4-)("purple colouration")`
`S^(2+)+BaCl_(2)rarr"No precipitate".`
`(b)" "2NO_(3)^(-)+4H_(2)SO_(4)+6Fe^(2+)rarr6Fe^(3+)+2NOuarr+4SO_(4)^(2-)+4H_(2)O`
`[Fe(H_(2)O)_(6)]^(2+)+NOrarrunderset(("Brown complex"))([Fe(H_(2)O)_(5)NO]^(2+)+H_(2)O)`
`(c )" "2I^(-)+CL_(2)+I_(2)+2Cl^(-)`
`" "I_(2)+C CI_(4)rarrI_(2)` dissolves forming a violet solution.
`(d)" "Ba^(2+)+SO_(4)^(2-)rarrBaSO_(4)darr("white")`
`HCl` removes the impurities of `S^(2-),I^(-)` and `NO_(3)^(-)` and white precipitate of `BaSO_(4)` is thus obtained.