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Find the speed of the ring as a function...

Find the speed of the ring as a function of '`theta`' if rope is pulled down with constant speed u:-

A

`(u)/(sin theta)`

B

`(u)/(cos theta)`

C

`(u)/(2 sin theta)`

D

`(u)/(2 cos theta)`

Text Solution

Verified by Experts

The correct Answer is:
B
Let speed of ring he v then ` v cos theta=u rArr v=(u)/(cos theta)` (`because` Magnitude of velocity along the string of any two points on string is same.)
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