क्षेत्र `{(x,y):0leylex^(2)+1,0le ylex+1,0lexle2}` का क्षेत्रफल ज्ञात कीजिए |

The area (in sq. units) of the region {(x,y):0leylex^(2)+1,0leylex+1,(1)/(2)lexle2} is

Find the area of the region {(x,y):0leylex^2+1, 0leylex+1, 0lexle2}

Find the area of region {(x,y):0leylex^(2)+1, 0 le y le x+ 1, 0 le x le 2} .

dy/dx का मान ज्ञात कीजिए यदि x=2at,y=at^2

If 3x^2-5x+1=0 , then the value of (x^2+ 1/(9x^2)) is : यदि 3x^2-5x+1=0 , तो (x^2+ 1/(9x^2)) का मान ज्ञात कीजिए ।

If the line x = alpha divides the area of region R = {(x,y) in R^(2) : x^(0) le y le x, 0 le x le 1} into two equal parts, then

Find the area bounded by the curves 0leylex^2+1,0le ylex+1,1/2le xle2