Draw a rough sketch of the region `{(x,y): y^2 le 3x,3x^2 + 3y^2 le16 }` and find the ara enclesed by the region using the method of intergraion

Draw a rough sketch of the region {(x,y) : y^(2)le 6 a x and x^(2)+y^(2)le 16 a^(2)} . Also, find the area of the region sketched using method of integration.

Draw a rough sketch of the following region and find the area enclosed by the region, using method of integration : {(x,y): y ^(2) le 5x, 5x ^(2) + 5y ^(2)le 36}.

S={3x^2 le 4y le 6x+2y} find the area

Find the area of the region {(x,y) : x^2 le y le x }

The area of the region {(x,y): xy le 8,1 le y le x^(2)} is :

Find the area of the region {(x,y):x^2 le y le |x| }.

Make a rough sketch of the graph of y = cos ^(2) x, 0 le x le (pi)/(2) and find the area enclosed between the curve and the axes.

Find the area of the region [x,y): x^2+y^2 le 1 le x+ y }

The area of the region {(x,y):x^(2)+y^(2) le 1 le x+y} , is

Find the area of the region [ (x,y) :x^2 le y le x )