Find the area common to the circle `x^2+y^2=16a^2` and the parabola `y^2=6ax,agt0.`

Explanation

On Solving the two equations, we have ` x^{2}+6 a-16 a^{2}=0`

or ,`({x}+8 {a})({x}-2 {a})=0 `

`therefore quad {x}=2 {a} `

`therefore quad {y}=pm 2 sqrt{3 {a}}`


The required common area =2[{APOA}]


`=2 int y d x+2 int y d x `

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