A particle of mass m, kinetic energy K and momentum p collision head on elastically with another particle of mass `2 m` at rest. After collision. :
`{:(,"Column I",,"Column II",),((A),"Momentum of first particle",(p),3//4 p,),((B),"Momentum of second particle",(q),-K//9,),((C ),"Kinetic energy of first particle",(r ),-p//3,),((D),"Kinetic energy of second particle",(s),(8K)/(9),),(,,,"None",):}`

Answer

(A) `rarr` r; (B) `rarr` t; (C ) `rarr` t; (D) `rarr` s

Explanation

By applying conservation of momentum

`m_(1)u_(1) + 2m(0) = mv_(1) + 2mv_(2)` …..(i)
Also `u = v_(2) - v_(1)` …….(ii)
`v_(2) = (2v)/(3)` and `v_(1) = -(v)/(3), F_(2) = (4mv)/(3) = (4p)/(3)`,
`P_(1) = -(mv)/(3) = -(P)/(3), K_(2) = (8K)/(9), K_(1) = (K)/(9)`