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Comprehension # 5 One particle of mass...

Comprehension # 5
One particle of mass `1 kg` is moving along positive x-axis with velocity `3 m//s`. Another particle of mass `2 kg` is moving along y-axis with `6 m//s`. At time `t = 0, 1 kg` mass is at `(3m, 0)` and `2 kg` at `(0, 9m), x - y` plane is the horizontal plane. (Surface is smooth for question 1 and rough for question 2 and 3)
The centre of mass of the two particles is moving in a straight line which equation is :-

A

`y = x + 2`

B

`y = 4x + 2`

C

`y = 2x - 4`

D

`y = 2x + 4`

Text Solution

Verified by Experts

The correct Answer is:
B

`vec(r )_(cm) = (m_(1)vec(r )_(10) + m_(2) vec(r )_(2))/(m_(1) + m_(2)) = (1 (3 hat(i)) + 2 (9 hat(j)))/(1 + 2) = (hat(i) + 6hat(j))m`
`vec(v)_(cm) = (m_(1) vec(v)_(1) + m_(2)vec(v)_(2))/(m_(1) + m_(2)) = (1(3hat(i)) + 2(6hat(j)))/(1 + 2) (hat(i) + 4hat(j))m//s`
Now `Deltavec(r )_(cm) = vec(v)_(cm) t rArr vec(r )_(cm) - vec(r)_(cm_(0)) = vec(v)_(cm) t`
`rArr (x - 1)hat(i) + (y - 6) hat(j) = (hat(i) + 4hat(j)) t`
`rArr x = 1 + t` and `y = 6 + 4t rArr y = 4x + 2`
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