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The 4 kg sphere form rest when theta = 6...

The `4 kg` sphere form rest when `theta = 60^(@)` strikes a block mass of `5 kg` placed on a rough horizontal plane and comes to rest after collision. The `5 kg` block comes to rest after moving a distance of `0.8m`. Find `mu` of ground & block & coefficient of restituation e.

Text Solution

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The correct Answer is:
`e = 0.8, mu = 0.4`
`u_(s) = sqrt(2g(1 - cos 60^(@))) = sqrt(2g xx (1)/(2)) = 3.13 m//s`
`COLM rArr 5u_(B) = 4 xx u_(s) rArr u_(B) = (4)/(5) sqrtg = 2.53 m//s`
Energy equation `(1)/(2)m ((4)/(5) sqrtg)^(2) = mu mg xx 0.8 rArr mu = 0.4`
`e = -((v_(2) - v_(1))/(u_(2) - u_(1))) = 0.8`
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