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Form the differential equation correspon...

Form the differential equation corresponding to `(x-a)^2+(y-b)^2=r^2` by eliminating a and b.

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To form the differential equation corresponding to the equation \((x-a)^2 + (y-b)^2 = r^2\) by eliminating the constants \(a\) and \(b\), we can follow these steps: ### Step-by-Step Solution: 1. **Start with the given equation**: \[ (x - a)^2 + (y - b)^2 = r^2 \] ...
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RD SHARMA-DIFFERENTIAL EQUATION-Solved Examples And Exercises
  1. Find the differential equation of the family of curves, x=A\ cos n ...

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  2. Form the differential equation corresponding to y^2=a(b-x^2) by elimin...

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  3. Form the differential equation corresponding to (x-a)^2+(y-b)^2=r^2 by...

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  4. Find the differential equation of all the circles which pass throug...

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  5. Find the differential equation of all the circles which pass thorou...

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  6. Assume that a rain drop evaporates at a rate proportional to its su...

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  7. Find the differential equation of all the parabolas with latus rectum ...

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  8. Form the differential equation of the family of curves represented by ...

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  9. Represent the following families of curves by forming the correspond...

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  10. Represent the following families of curves by forming the correspondin...

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  11. Represent the following families of curves by forming the correspondin...

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  12. Represent the following families of curves by forming the correspondin...

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  13. Represent the following families of curves by forming the correspond...

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  14. Represent the following families of curves by forming the correspondin...

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  15. Form the differentials equation representing the family of ellipse h...

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  16. Form the differential equation of the family of hyperbola having fo...

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  17. Form the differential equation of the family of circles in the seco...

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  18. Show that x y=a e^x+b e^(-x)+x^2 is a solution of the differential equ...

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  19. Verify that the function y=C1e^(a x)cosb x+C2e^(ax)sinb x ,\ C1, C2,\ ...

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  20. Show that y=b e^x+c e^(2x)\ is a solution of the differential equatio...

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