Find the differential equation of all the circles which pass thorough the origin and whose centres lie on x-axis.

Explanation

To find the differential equation of all circles that pass through the origin and whose centers lie on the x-axis, we can follow these steps:

### Step 1: Write the general equation of the circle
The general equation of a circle with center at \((a, 0)\) and radius \(a\) is given by:
\[ (x - a)^2 + (y - 0)^2 = a^2 \]

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