Show that `y=a x^3+b x^2+c` is a solution of the differential equation `(d^3y)/(dx^3)=6a`.

Explanation

Given,


`y=a x^3+b x^2+c`


Differentiating w.r.t `x`


`y'=3ax^2+2bx`


Differentiating w.r.t `x`


`y''=6ax+2b`


Differentiating w.r.t `x`


`y'''=6a`


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