Solve: `(e^x+e^(-x))dy/(dx)=(e^x-e^(-x))`

Explanation

`frac{d y}{d x}=frac{e^{x}-e^{-x}}{e^{x}+e^{-x}}`


Take `v=e^{x}+e^{-x}`

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Rightarrow d v=(e^{x}-e^{-x}) d x`

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Rightarrow int d y=int frac{1}{v} d v+c`

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Rightarrow y=log v+c`

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y=log (e^{x}+e^{-x})+c`

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