Solve the following differential equation: `(dy)/(dx)=logx`

Explanation

`frac{d y}{d x} =log x `


`therefore d y =log x d x`



By Integrating , we obtain



`int 1 {dy}=int(log {x} times 1) {dx} `


`therefore y=log x(int 1 d x)-int[frac{d}{d x}(log x) int 1 d x] `


`therefore y=log x(x)-int(frac{1}{x} times x) d x `


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