Solve the initial value problem: `(x+1)(dy)/(dx)=2e^(-y)-1,\ y(0)=0`

Explanation

It is given that

$$ (x+1) \frac{d y}{d x}=2 e^{-y}-1 $$
Bifurcate the terms of `y` and `x` w.r.t to `dy` and `d x` respectively, we get
$$ \frac{d y}{2 e^{-y}-1}=\frac{d x}{x+1} $$
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