Solve the following differential equation: `dy+(x+1)(y+1)dx=0`

Explanation

`d y+(x+1)(y+1) d x=0`


`Rightarrowd y=-(x+1)(y+1) d x`


On integrating both sides we get,


`Rightarrowint frac{d y}{y+1}=-int(x+1) d x `


`Rightarrowlog |y+1|=-frac{x^{2}}{2}-x `


`Rightarrowlog |y+1|+frac{x^{2}}{2}+x+C`