Solve the following initial value problem: `2(y+3)-x y(dy)/(dx)=0,\ y(1)=-2`

Explanation

Given that,

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` 2(y+3)-x y frac{d y}{d x}=0`

`Rightarrow 2(y+3)=x y frac{d y}{d x}`

`Rightarrow 2 frac{d x}{x}=frac{y}{y+3} d y `

`Rightarrow 2 int frac{d x}{x}=int(1-frac{3}{y+3}) d y `

`Rightarrow 2 log x=y-3 log (y+3)+C`

Given that when

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