Solve the following differential equation: `3x^2dy=(3x y+y^2)dx`

Explanation

$$ 3 x^{2} d y=\left(3 x y+y^{2}\right) d x $$
$$ \frac{d y}{d x}=\frac{3 x y+y^{2}}{3 x^{2}} \ldots \ldots . .(1) $$
Let `y=t x`
,Then, `\frac{d y}{d x}=t \frac{d t}{d x}`

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