Solve each of the following initial value problem: `(x^2+y^2)dx=2x y\ dy ,\ y(1)=0`

Explanation

$$ \begin{aligned} &\left(x^{2}+y^{2}\right) d x=2 x y d y, y(1)=0 \\ &\frac{d y}{d x}=\frac{x^{2}+y^{2}}{2 x y} \end{aligned} $$
It is a homogeneous equation.
Put `y=v x`
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