Solve the following differential equation: `((x^2-1)dy)/(dx)+2x y=1/(x^2-1);\ |x|\ !=1`

Explanation

Given that,

``
`(x^{2}-1) frac{d y}{d x}+2 x y=frac{1}{x^{2}-1}`

`=> quad frac{d y}{d x}+(frac{2 x}{x^{2}-1}) y=frac{1}{(x^{2}-1)^{2}}`

``
which is a linear differential equation.

On comparing it with `frac{d y}{d x}+P y=Q`,

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