Solve the following differential equation: `dx+x dy=e^(-y)sec^2y\ dy`

Explanation

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`d x+x d y=e^{-y} sec ^{2} y d y `


`frac{d x}{d y}+x=e^{-y} sec ^{2} y`


`I . F=e^{int 1 d y}=e^{y}`


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Thus required solution is,


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`x e^{{y}}=int {e}^{{y}} cdot {e}^{-{y}} sec ^{2} {ydy}=int sec ^{2} {ydy}=tan {y}+{c}`
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