Solve the following initial value problem: `(dy)/(dx)+2 tanx cdot y=sinx ; y=0\ w h e n\ x=\ pi/3` .

Explanation

To solve the initial value problem given by the differential equation

\[ \frac{dy}{dx} + 2 \tan x \cdot y = \sin x \]

with the initial condition \( y = 0 \) when \( x = \frac{\pi}{3} \), we will follow these steps:

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