The general solution of the differentia equation `(dy)/(dx)+ycotx = cos e c x ,`is (a). `x+y \ sin\x=C` (b). `x+y cos\ x=C` (c). `y+x(sin x+cos x)=C` (d). `y \ sinx=x+C`

Explanation

`frac{d y}{d x}+y cot x=cosec x `


`frac{d y}{d x}+y cot x=cosec x`



By Comparing with frac{d y}{d x}+P y=Q, we obtain



`P=cot x `


`Q={cosec} x`


` I. F .=e^{int cot x d x}=e^{log (sin x)} `


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