The differential equation `(dy)/(dx)+P y=Q y^n ,\ n >2` can be reduced to linear form by substituting a. `z=y^(n-1)` b. `z=y^n` c. `z=y^(n+1)` d. `z=y^(1-n)`

Explanation

To solve the problem of reducing the differential equation \(\frac{dy}{dx} + Py = Qy^n\) (where \(n > 2\)) to a linear form, we will follow these steps:

### Step 1: Rewrite the Equation
Start with the given differential equation:
\[ \frac{dy}{dx} + Py = Qy^n \]
To make it easier to manipulate, we can divide the entire equation by \(y^n\):
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