Integrating factor of differential equation `cosx(dy)/(dx)+ysinx=1` is

Explanation

Given that, `cos x frac{d y}{d x}+y sin x=1`


Dividing both sides by `cos {x}`,


`Rightarrow frac{d y}{d x}+y tan x=sec x`


Here, `{P}=tan {x}` and `{Q}=sec {x}`


`I F=e^{int y d x} e^{int tan x d x}=e^{log sec x}`


`therefore I.F. = sec x`