Solve the differential equation: `(dy)/(dx)-\ ycot\ x=cos e c\ x`

Explanation

$$d y / d x+y \cot x=\operatorname{cosec} x$$
The above equation is of the form $$\frac{d y}{d x}+P y=Q$$ I.e. linear differential equation.
Here, `P=cot x` and `Q=cosecx`
Integrating factor `=e^{\int p d x}`
Considering `P`
$$
\begin{aligned}
&\Rightarrow \int P d x=\int \cot x d x \\
...