Solve the following differential equation: `(x^2+1)dy+(2y-1)dx=0`

Explanation

It is given that
$$
\begin{aligned}
&\left(x^{2}+1\right) d y+(2 y-1) d x=0 \\
&\Rightarrow \frac{d y}{d x}=\frac{(1-2 y)}{\left(x^{2}+1\right)} \\
&\Rightarrow \frac{d y}{d x}+\frac{2 y}{x^{2}+1}=\frac{1}{x^{2}+1}
\end{aligned}

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