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[sin^(6)theta+cos^(6)theta+3sin^(2)theta...

[sin^(6)theta+cos^(6)theta+3sin^(2)theta*cos^(2)theta=],[hline0],[1],[hline2],[hline3]

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sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1

sin^(6)theta+cos^(6)theta=1-3sin^(2)thetacos^(2)theta

sin^(6)theta=cos^(6)theta=1-3sin^(2)thetacos^(2)theta

sin ^(6) theta+cos ^(6) theta+3 sin ^(2) theta . cos ^(2) theta=

Prove that sin^(6)theta+cos^(6)theta+3sin^(2)thetacos^(2)theta=1

int(sin^(6)theta+cos^(6)theta)/(sin^(2)theta cos^(2)theta)d theta=

Prove that sin^(6)theta+cos^(6)theta=1-3sin^(2)theta cos^(2)theta

Prove that sin^(6)theta+cos^(6)theta=1-3sin^(2)theta.cos^(2)theta.

2(sin^(6) theta + cos^(6)theta) - 3(sin^(4)theta + cos^(4)theta)+ 1 = 0

The value of the expression sin^(6)theta+cos^(6)theta+3sin^(2)theta*cos^(2)theta equals