If `5pi <= x <= 6pi,` then the value of `cos^-1(cosx)`is equal to

Express sin "" (5pi)/(2) in terms of cos 5pi ,

Express the following numbers in the form x+iy 7 ( cos ( - ( 5pi )/( 6)) + i sin ( - ( 5pi )/( 6)))

Find all values of x such that - 5pi le x le 5pi and cos x = 1

The displacement of a particle is given by x = 3 sin ( 5 pi t) + 4 cos ( 5 pi t) . The amplitude of particle is

The displacement of a particle is given by x = 3 sin ( 5 pi t) + 4 cos ( 5 pi t) . The amplitude of particle is

The function whose period is 5 pi is

The function whose period is 5 pi is

(cos pi) / (5) + (cos (2 pi)) / (5) + (cos (6 pi)) / (5) + (cos (7 pi)) / (5) = 0