The foot of the perpendicular from the point (1,2,3) on the line `vecr=(6hati+7hatj+7hatk)+lamda(3hati+2hatj-2hatk)` has the coordinates

Find the perpendicular distance from the point (1,2,3) to the line : vecr=6hati+7hatj+7hatk+lambda(3hati+2hatj-2hatk)

The length of perpendicular from the origin to the line vecr=(4hati+2hatj+4hatk)+lamda(3hati+4hatj-5hatk) is

The position vector of the foot of the perpendicular draw from the point 2hati-hatj+5hatk to the line vecr=(11hati-2hatj-8hatk)+lamda(10hati-4hatj-11hatk) is

The position vector of the foot of the perpendicular draw from the point 2hati-hatj+5hatk to the line vecr=(11hati-2hatj-8hatk)+lamda(10hati-4hatj-11hatk) is

The length of perpendicular from the origin to the line vecr=(4hati=2hatj+4hatk)+lamda(3hati+4hatj-5hatk) is (A) 2 (B) 2sqrt(3) (C) 6 (D) 7

The length of perpendicular from the origin to the line vecr=(4hati+2hatj+4hatk)+lamda(3hati+4hatj-5hatk) is (A) 2 (B) 2sqrt(3) (C) 6 (D) 7

Find the equation of the line perpendicular to the lines : vecr=(3hati+2hatj-4hatk)+lambda(hati+2hatj-2hatk) and vecr=(5hatj-2hatk)+mu(3hati+2hatj+6hatk) and passing through the point (1,1,1)

The vector equation of the plane containing he line vecr=(-2hati-3hatj+4hatk)+lamda(3hati-2hatj-hatk) and the point hati+2hatj+3hatk is

The vector equation of the plane containing he line vecr=(-2hati-3hatj+4hatk)+lamda(3hati-2hatj-hatk) and the point hati+2hatj+3hatk is