Assertion : `LiAlH_(4)` is more reactive and less selctive than `NaBH_(4)` as a reducing agent.
Reason : `LiAlH_(4)` reduces both aldehydic group and double bond in conjugate position while `NaBH_(4)` does not.

LiAlH_4 / ether reduces methyl cyanide into

Reduction OF (LiAlH4 or LAH, NaBH4) and Examples

The compound formed by reducing acetone with LiAlH_(4) is :

Acetic acid can be reduced by LiAlH_(4) to :

Carbon oxygen double bond are easily reduced by NaBH_(4) or LiAlH_(4) . The actual reducing agent in these reduction is hrdride ion (H^(-)) The metal hydrogen bond in LiAlH_(4) is more than polar than metal hydrogen bond in NaBH_(4) . As a result LiAlH_(4) is strong reducing agent than NaBH_(4) . Esters, carboxylic acids, amides cannot be reduced by NaBH_(4) The carbonyl group of amide of reduced to methylene group by LiAlH_(4)

Carbon oxygen double bond are easily reduced by NaBH_(4) or LiAlH_(4) . The actual reducing agent in these reduction is hrdride ion (H^(-)) The metal hydrogen bond in LiAlH_(4) is more than polar than metal hydrogen bond in NaBH_(4) . As a result LiAlH_(4) is strong reducing agent than NaBH_(4) . Esters, carboxylic acids, amides cannot be reduced by NaBH_(4) The carbonyl group of amide of reduced to methylene group by LiAlH_(4) Find the correct product of the following reaction: